12 lines
412 B
Python
12 lines
412 B
Python
from datetime import datetime, timedelta
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def get_last_friday(a: str) -> str:
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date = datetime.strptime(a, "%m/%Y").date()
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next_month = date.replace(day=28) + timedelta(days=7)
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last_day = next_month - timedelta(days=next_month.day)
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# Идем назад до пятницы
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while last_day.weekday() != 4:
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last_day -= timedelta(days=1)
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return last_day.strftime("%d.%m.%Y") |